How long is a leg a of a right triangle
whose other leg b measures 2x units,
and whose hypotenuse c measures 4x units
(where x 0) ?

Question

How long is a leg  a of a right triangle 
whose other leg  b measures  2x units,  
and whose hypotenuse  c measures  4x units 
(where x 0)  ?

anonymous · Answer

this is sq root ((2x)^2 + (4x)^2))

anonymous · Answer

oopps - sorry  it is sq root((4x)^2 - (2x)^2))

anonymous · Answer

$$(4x)^{2}-(2x)^{2}$$

anonymous · Answer

this comes to sq root12 x^2

anonymous · Answer

$$16x^{2}-4x ^{2}=12x ^{2}$$$$\sqrt{12x ^{2}}=2x \sqrt{3}$$

anonymous · Answer

$$\frac{\sqrt{3}}{2}x $$

anonymous · Answer

Thank you so much! I havent had math in a year and I'm trying to review some math

anonymous · Answer

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anonymous · Answer

How do I do that..

anonymous · Answer

next to my name click give medal

anonymous · Answer

what u see ,give medal or good answer?

anonymous · Answer

$$4x \text{Cos}[\text{ArcSin}[(2x)/(4x)]] =2 \sqrt{3} x $$
I forgot to multiply by 4x

anonymous · Answer

thank

myininaya · Answer

$$2x \sqrt{4-x^2}$$

myininaya · Answer

its a right triangle so we have a^2+b^2=c^2
c=4x
b=2x
a=?
a^2=c^2-b^2
a=sqrt{c^2-b^2}
a=sqrt{(4x)^2-(2x)^2}
a=sqrt{16x^2-4x^2}
a=sqrt{4x^2}sqrt{4-1}
a=2xsqrt{3}
oh i made a mistake lol
i guess it helps when u work it out