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Find the center, foci , asymptotes of the hyperbola y^2 - x^2 - 4y + 10x -70 = 0
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+4+25 = +29+70 = 99 hmmm (y-2)(x+5) center = (-5,2)
(y-2)^2 (x+5)^2 ------ - ------- = 1 99 99 its a square under there lol.... a and b = sqrt(99) vertex is along the y so (-5, 2+sqrt(99)) and (-5, 2-sqrt(99))
asymps are y = +-(x+5) +2 right?
maybe not lol
its a 45 from x = -5,2 y = +- (x+5)+2 y = x+7 and y = -x-3 maybe
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foci are... what; sqrt(198) from center right? (-5,2-sqrt(189))(-5,2+sqrt(189)) if i did it right lol
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