Question

Given: ABC is similar to XYC. Enter answer as a simplified, improper fraction.

If BY = 4, YC = 7, XC = 10, then AC

Answer 1

I think is is 9/2

Answer 2

\[AC = \frac{110}{7}\]BC=7+4=11
AC=AX+10
\[\frac{10}{7}=\frac{AX+10}{11}\]cross and time
10*11=7AX+70
110 =7AX+70
AX =(110-70)/7
AX =40/7
AC= AX +10
\[AC= \frac{40}{7}+10\]
deniminator is 7
\[ AC =\frac{40+70}{7} \]
\[AC= \frac{110}{7}\]
if u want decimal u caculater

Answer 3

If I deserve medal then give me one