Question

solve the diff. eq.: du/dt = e^-2u.

Answer 1

Try to sevarate the varibale
\(e^{2u}du=dt\)
Now integrate!

Answer 2

du/dt = e^(-2u)
e^(2u) du = dt
Integrate both sides, don't forget the constant.

Answer 3

i came up with u = (ln(2t + c)) / 2... sound right?