Question

find the x and y intercepts for f(x)=x^2-8x+1

Answer 1

For x-intercepts, set x = 0. You get f(x) = 1.

For y-intercepts, set f(x) = y = 0. Use the quadratic formula or factor/complete the square.

Answer 2

plug x=0 solve fo y\[y=0^{2}-8(0)+1\]\[y=1\]
plug y=0 solve for x
\[0=x^{2}-8x+1\]
\[\frac{-b \pm \sqrt{b ^{2}-(4\times a \times c} }{2\times a}\]
a=1
b=-8
c=1

can u slove for x?

Answer 3

x=4+or-sqrt3?

Answer 4

\[\frac{-(-8)\pm \sqrt{-8^{2}-(4\times 1\times 1)}}{2 \times 1}\]\[\frac{8\pm \sqrt{64-4}}{2}= \frac{8\pm \sqrt{60}}{2}\]\[\frac{8\pm2\sqrt{15}}{2}=4\pm \sqrt{15}\]

Answer 5

oops i added it.

Answer 6

If I deserve medal then give me one

Answer 7

T Y