Question

In the problem Express the solution of the initial-value problem y'-2xy=1,y(1)=1, in terms of erf(x), what is erf(x)?

Answer 1

This is the quadratic Equation x=(-b±√(b^2-4ac))/2a

au^2+bu+c=0

Answer 2

So I must now put initial value problem in linear equation format and subtract c over?

Answer 3

I realize now y' does not equal y^2.

Answer 4

I found the differential equation y=-3x^-3+cx^-3