Question

prove the statement true :
1^2 +4^2 + 7^2 + ..... + (3n-2)^2 = [n (6n^2 - 3n -1)] / 2

Answer 1

Hint: Direct use of Induction

Answer 2

this is not true for n=2

Answer 3

are you sure u type this incorrectly?

Answer 4

24-6-1=17 not 16

Answer 5

nvm im wrong i forgot to 1 to the lhs
so it does hold for n=2