Question

9y^2-8x^2+72y+16x+64=0

give the exact coordinates of any four points on the hyperbola

Answer 1

hi can u help me

Answer 2

let y be 0
8x^2 - 16x - 64 = 0
x^2 - 2x - 8 = 0
x = 4 or -2
therefore 2 points are (-2,0) and (4,0)
now let x be 0
9y^2 + 72y + 64 = 0
y = -1.01 or -6.98
therefore the next 2 points are (0,-1.01) and (0, -6.98)

Answer 3

i dont think the (0,-1.01) and (0, -6.98) are correct

Answer 4

i think we should let y be something and solve for x