Question

pls help ..integrate (tan^-1y)/(1+y^2)

Answer 1

use u substitution
u = tan^-1(y)
du = 1/(1+y^2) dy --> dy = (1+y^2)du

= integral u du
= 1/2 u^2 + C
=1/2(tan^-1(y))^2 + C

Answer 2

thanks

Answer 3

no prob