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Mathematics 61 Online
OpenStudy (anonymous):

solve the following equation for x: 3^2x =15

OpenStudy (anonymous):

one way to solve it is to take the log of it :\[\log_{3} 15 = 2x\]\[\log_{3} 15\approx2.46\] 2.46 = 2x x = 1.23 Correct me if I'm wrong ^_^

OpenStudy (anonymous):

thank you

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