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OpenStudy (anonymous):
solve for x log5x+log3=0 please explain
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OpenStudy (anonymous):
minus log3 on each side then divide by 5
OpenStudy (anonymous):
multiply e both sides
OpenStudy (angela210793):
log5x*3=log1 15x=1 x=15
OpenStudy (angela210793):
loga+logb=log(a*b)
OpenStudy (anonymous):
\[e ^{\log(5x)+\log(3)}=5x(3) =15x\] \[e^0 = 1\] 15x=1 x = 1/15
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OpenStudy (angela210793):
yea sorry X=1/15 :)
OpenStudy (angela210793):
There was no need to use e :)
OpenStudy (anonymous):
true
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