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OpenStudy (anonymous):
\[g(x)=\frac{x-3}{x(x+1)}\]
OpenStudy (anonymous):
what is the question?
OpenStudy (anonymous):
yes find the vertical asymptotes if any
OpenStudy (anonymous):
set denominator = 0 and solve:\[x(x+1)=0\]
\[x=0\] or \[x=-1\] so there are two.
OpenStudy (anonymous):
need the horizontal one as well? degree of numerator is 1,degree of denominator is 2, and since 2 > 1 it is \[y=0\]
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OpenStudy (amistre64):
gotta make sure that the bottom doesnt cancel the top; if it does, that would be a hole; but this problem is good....
OpenStudy (anonymous):
thanks
OpenStudy (anonymous):
\[\log_{c}t+\log_{c}s \]
OpenStudy (amistre64):
logc(ts)
OpenStudy (anonymous):
\[log_c(ts)\]
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OpenStudy (anonymous):
hello again.
OpenStudy (anonymous):
oh so the bases never changes when re-writing??
OpenStudy (amistre64):
not in that case :)
OpenStudy (anonymous):
if they are different you cannot do it.
OpenStudy (anonymous):
k thanks ...was always confused about that..lol teachers dont kno what they are talking about..lol
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OpenStudy (anonymous):
typical
OpenStudy (anonymous):
pre-calc class?
OpenStudy (anonymous):
sort of its a new thing in orlando ..its a college readiness class that is basically preparing you to take pre-calc in college
OpenStudy (anonymous):
\[\frac{2x}5=\frac{x}3+2;solve\]
OpenStudy (toxicsugar22):
i amristre can u help me after her
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OpenStudy (amistre64):
orlando eh... im over near brooksville
OpenStudy (amistre64):
perhaps :) hypers are easy
OpenStudy (toxicsugar22):
amristre can u help me after her
OpenStudy (amistre64):
*15 all of it....
6x = 5x +30
x = 30 maybe?
OpenStudy (amistre64):
dbl check
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OpenStudy (toxicsugar22):
amristre can u help me after
OpenStudy (amistre64):
60/5 = 30/3 +2
6 = 10+2 .... gonna have to see what I did lol
OpenStudy (amistre64):
i can yes...
OpenStudy (amistre64):
2x x
--- = --- + 2
5 3
2x = 5x/3 +10
2x = 5x+30/3
6x = 5x +30
x = 30 .....
2(30) 30
---- = --- + 2
5 3
2(6) = 10 + 2
12 = 12 ; well it worked that time lol.. my dbl check must have been off
OpenStudy (amistre64):
60/5 = 12 lol.....
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OpenStudy (anonymous):
answer is either -+30 or -+60..but thanks lol
OpenStudy (amistre64):
x = 30 fer sure
OpenStudy (anonymous):
ok her is my impossible problem...lol
OpenStudy (anonymous):
x^2+7x+10 times x^2+6x
---------- ----------- multiply
x^2+8x+12 x^2+13x+40
OpenStudy (amistre64):
factor to see what cancels...
2,5,x,6
------
6,2,8,5
,,x,
--- = x/(x+8) if I see it right
,,8,
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OpenStudy (anonymous):
brilliant!
OpenStudy (anonymous):
but can you walk me through it so i can no how to do it myself