Question

What is the center of a circle with the equation x^2-8x+y^2-10y+5??

Answer 1

What is the right hand side of this equation? (where is the = sign?)

Answer 2

It equals 0.

Answer 3

Complete the square.

Answer 4

\[x^2 - 8x + y^2 - 10y + 5\]
\[(x^2 - 8x + 16) + (y^2 - 10y + 25) + 5 - 16 - 25\]
\[(x-4)^2 + (y-5)^2 = 6^2\]
center is (4, 5)
radius is 6