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how do you divide x+5/x+3 / x+6/x^2+9x+18 please help and explain
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Which line is the 'big' divider.
= x+6
the middle /
sorry correct answer should be x+5
will show work next
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A/B/C/D=AD/BC
\[(x+5)/(x+3) \div (x+6)/(x^2+9x+18)=\] since \[x^2+9x+18 = (x+3)(x+6)\] then we have\[(x+5)/(x+3)\times(x+3)(x+6)/(x+6) =\] cancel (x+3) and (x+6) x+5 left! hope it helps!
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