Question

What is the range of f(x) =
\[2 - \log_{3}(3 + x) \]

Answer 1

the domain would be x>-3; the range is still (-inf,inf) tho; all you did was flip it and raise it

Answer 2

Thank you! I have been trying to figure out if there is a range change for half an hour now. Do you by chance know how I can get the y intercept?

Answer 3

yeah, set x = 0 :)

Answer 4

log3(3) = 1 so; 2-1

Answer 5

Thank you! So just to sum it up,
Domain = (-3, inf)
Range = (-inf, inf)
Asymptote = x=-3
y intercept = y=1 ???

Answer 6

y int = (0,1) but yeah...thats pretty much it

Answer 7

Thanks!