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Mathematics
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determine the vertical asymptotes and the end behavior of the following function. ((x^3/3)-(x^2/4)-2X-1)/((2-3x)(x+1)(2x-3))
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the top gets us an x^3 -------------------- the bottom gets us an x^3 so all thats left is the leading coeffs in the end.... for the ha
1/3 ---- = -1/18 as the ha if i see it right -6
nothing cancles top to bottom so the zeros in the bottom make the vas
2/3, -1, and 3/2
i wonder what happens when I report abuse myself lol
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lol what do you mean? am i abusing you?
wait where is the -6 come from?
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