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OpenStudy (anonymous):
r^2+3r-10=0 solutions are? I got answers (2,-5), can anyone please tell me if that is right???????????
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OpenStudy (amistre64):
looks right
OpenStudy (amistre64):
-(5,-2) so yeah
OpenStudy (anonymous):
yah thats ryt
OpenStudy (anonymous):
bec (r+5)(r-2)=0 then first solution is r=-5 and r=2
OpenStudy (anonymous):
the order is (2,-5)not (-5,2)
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