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OpenStudy (anonymous):

r^2+3r-10=0 solutions are? I got answers (2,-5), can anyone please tell me if that is right???????????

OpenStudy (amistre64):

looks right

OpenStudy (amistre64):

-(5,-2) so yeah

OpenStudy (anonymous):

yah thats ryt

OpenStudy (anonymous):

bec (r+5)(r-2)=0 then first solution is r=-5 and r=2

OpenStudy (anonymous):

the order is (2,-5)not (-5,2)

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