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Mathematics 12 Online
OpenStudy (anonymous):

solve. absol val x+3/3 absol val >1

OpenStudy (anonymous):

\[\left| x+3/3 \right|<1\]

OpenStudy (anonymous):

solve for.

OpenStudy (anonymous):

\[ \frac{|x+3|}{3}>1\]?

OpenStudy (anonymous):

if so then \[|x+3|>3\] \[x+3>3\]or \[x+3<-3\] first one gives \[x>0\] second gives \[x<-6\]

OpenStudy (anonymous):

so those are the two intervals,

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