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Mathematics 12 Online
OpenStudy (anonymous):

any idea what this is. solve. |x+3/3|<1

OpenStudy (amistre64):

the only solution is to make it between 0 and 1

OpenStudy (amistre64):

x+3 <3; x<0 for one option

OpenStudy (amistre64):

-x-3 <3 -x <6 x> -6

OpenStudy (amistre64):

so x is between (-6,0)

OpenStudy (anonymous):

ok. thanks

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