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Give the exact and approximate solutions to three decimal places. y^2-8y+16=36 y=?
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Move the 36 over. y^2-8y-20=0 Factor (quadratic formula). The rest you can do.. I am simply too lazy.
(y+2)(y-10)=0
so y=-2 and y=10
y+2=0...y=-2 y-10=0...y=10
yeah thats it ..lol
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so y=-2, 10
exact and approximate? who writes these?
justa check on...y.2x10=20...-10y+2y=8y...yxy=y^2
oops sory i mean check on....2(-10)=-20...-10y+2y=-8y...yy=y^2
thnx
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