4x^2-6y^2+32x-24y+16=0

give the exact coordinated of an four points

Question

4x^2-6y^2+32x-24y+16=0

give the exact coordinated of an four points

anonymous · Answer

Hello toxi,
Let's take $x=0$, then we will have $-6y^2-24y+16=0$. By solving the quadratic equation we get two values for y. That's $y=-2/3(3+\sqrt5)$ or $y=-2/3(3-\sqrt5)$.

anonymous · Answer

Those are already two points. Other two points can be found by plugging $y=0$, then
$4x^2+32x+16=0$, which gives the solutions $x=-2(2+\sqrt{3})$ and $x=-2(2-\sqrt{3})$.

toxicsugar22 · Answer

so what aret the points

toxicsugar22 · Answer

what are the points

toxicsugar22 · Answer

can u help me

anonymous · Answer

(0,-2/3(3+sqrt5),
(0,-2/3(3-sqrt5),
(-2(2+sqrt3),0),
(-2(2-sqrt3),0)

toxicsugar22 · Answer

thanks can u help me with one more

toxicsugar22 · Answer

12x^2-3y^2+24y-84=0 

give the exact coordinates of any four points on the hyperbola