Question

4x^2-6y^2+32x-24y+16=0

give the exact coordinated of an four points

Answer 1

Hello toxi,
Let's take \(x=0\), then we will have \(-6y^2-24y+16=0\). By solving the quadratic equation we get two values for y. That's \(y=-2/3(3+\sqrt5)\) or \(y=-2/3(3-\sqrt5)\).

Answer 2

Those are already two points. Other two points can be found by plugging \(y=0\), then
\(4x^2+32x+16=0\), which gives the solutions \(x=-2(2+\sqrt{3})\) and \(x=-2(2-\sqrt{3})\).

Answer 3

so what aret the points

Answer 4

what are the points

Answer 5

can u help me

Answer 6

(0,-2/3(3+sqrt5),
(0,-2/3(3-sqrt5),
(-2(2+sqrt3),0),
(-2(2-sqrt3),0)

Answer 7

thanks can u help me with one more

Answer 8

12x^2-3y^2+24y-84=0

give the exact coordinates of any four points on the hyperbola