Question

anwar are u there

Answer 1

lets try to group this 4x^2+32x-6y^2-24y+16=0 2x(2x+16)-6y(y+4)+16=0 2x(2x+16)=0 the solution is x=(0,8) -6y(y+4)=16 -6y=16 y=-8/3 y+4=16 y=16-4 y=12 solution is (8/3, 12)

Answer 2

I wrote the answer on your older post.