Question

(y^4+3y-1)/(y^2-3)

Answer 1

im guessing polynomial division

Answer 2

dumbcow is right, (y^4+3y-1)/(y^2-3) = y^2 + 3 + (3y + 8/y^2 - 3)

Answer 3

for most part its same steps as regular long division
do you need help with the steps

Answer 4

nothingmaster gave you the correct answer if thats all you need

Answer 5

im not sure how that answer is correct

Answer 6

(y^2-3)(y^2 +3 +(3y+8/y^2-3))
=y^4 +3y^2 -3y^2 -9 +(3y+8)
=y^4 +3y -1
which is the original numerator so quotient is correct