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√x^2negativex-12=x+3
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\(\sqrt{x^2-x-12}=x+3\) like that?
yes :)
When I tried putting the negative sign in front of the x and then minusing the 12 it thought I was trying to subtract the x
\(\sqrt{(x+3)(x-4)}=(x+3)\) Square both sides \((x+3)(x-4)=(x+3)(x+3)\) \((x+3)((x-4)-(x+3))=0\) \((x+3)(-7)=0\) Hence \(x=-3\) is the only answer.
Thank you !!!
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