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Mathematics 8 Online
OpenStudy (anonymous):

how do you simplify ln e ?

OpenStudy (anonymous):

ln e = log(e lower) e = 1

OpenStudy (anonymous):

\[ln(e)=1\] because \[e^1=e\]

OpenStudy (anonymous):

which follows from law log(lower a) a = 1

OpenStudy (anonymous):

\[e^x=y\] same as \[ln(y)=x\]

OpenStudy (anonymous):

lol

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