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what is the lonegest diagonal of a box thta is 3 by 6 by 6 and what is the problem and answer please!!
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the broadest face is 6 by 6 the diagonal of that is root(6^2 + 6^2) using pythagorus
or using the distance formula the distance between (0,0) and (6,6) is root(6^2 + 6^2)
same answer but using calculus
so i completley disregard the 3? and the answer is 72?
not 72 but the squre root of 72. if they want the longest diagonal of the whole box (i.e using the 3) then they want the distance between (0,0,0) and (6,6,3) which is root(6^2+6^2 + 3^2)
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which is 9 but since youre in 10th grade I donno if they'll expect you to know that
okay thank you veryyyyyyy muchhh:)
pleasure :)
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