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f(x)=2^3x+5 finding f^-1 (x) ?
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Is that \(f(x)=2^{3x}+5\)?
correcto
\(y=2^{3x}+5\) \(y-5=2^{3x}\) \(\log_2(y-5)=3x\) \(x=\frac{1}{3}\log_2(y-5)\) So \(f^{-1}(x)=\frac{1}{3}\log_2(x-5)\)
wow! thanx
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