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Solve the system, using substitution. 3a - b = 11 and 2a + 3b = 0 A. (3, 2) B. (3, -2) C. (-3, 2) D. (-3, -2) E. no solution I got B... correct?
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is this(a,b) or (b,a) ??
no matter what. i end up with a fraction. guessing it's E. no solution.
E. no solution
Hmm okie dokie! THanks (:
Solve the system, using substitution. y = 1 - 5x and 5x + y = 8 A. no solution B. infinitely many solutions
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I put B. is this right? its my last one ^^
1=8 and does not \[1\neq8\] there for it ha to be No solution. stop guessing. you are not doing well at that job.
Haha i am done!! (: :D thanks soooo much!!
u'r welcome. i tried.
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