Solve the system, using substitution.

3a - b = 11 and 2a + 3b = 0

A. (3, 2)
B. (3, -2)
C. (-3, 2)
D. (-3, -2)
E. no solution

I got B... correct?

Question

Solve the system, using substitution.

3a - b = 11 and 2a + 3b = 0

A. (3, 2)
B. (3, -2)
C. (-3, 2)
D. (-3, -2)
E. no solution

I got B... correct?

anonymous · Answer

is this(a,b) or (b,a) ??

anonymous · Answer

no matter what. i end up with a fraction. guessing it's E. no solution.

anonymous · Answer

E. no solution

anonymous · Answer

Hmm okie dokie! THanks (:

anonymous · Answer

Solve the system, using substitution.

y = 1 - 5x and 5x + y = 8

A. no solution
B. infinitely many solutions

anonymous · Answer

I put B. is this right? its my last one ^^

anonymous · Answer

1=8 
and does not $$1\neq8$$ there for it ha to be No solution. stop guessing. you are not doing well at that job.

anonymous · Answer

Haha i am done!! (: :D thanks soooo much!!

anonymous · Answer

u'r welcome. i tried.