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OpenStudy (anonymous):
The expression cos^2X - cos2X is equivalent to what?
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OpenStudy (anonymous):
you know that \[cos(2x)=cos^2(x)-sin^2(x)\] so \[cos^2(x)-cos(2x)=cos^2(x)-[cos^2(x)-sin^2(x)]=sin^2(x)\]
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