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Mathematics 7 Online
OpenStudy (anonymous):

Help again with a derivative, please? Anyone? need derivative of 2 sin 3x

OpenStudy (anonymous):

Using trig derivatives and the chain rule (d/dx of sin=cos) 2cos(3x)x3=6cos(3x) d/dx of 2sin3x equals 6cos3x

OpenStudy (anonymous):

gotcha! Thanks again so much!

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