Question

the square of a number is equal to 20 more than the number. find all such numbers

Answer 1

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Answer 2

Let the number be x then: \(x^2=20+x\), implies that \(x^2-x-20=0\). This can be factored into \((x-5)(x+4)=0\). Hence \(5\) and \(-4\) are the only two numbers that satisfy the given conditions.

Answer 3

n^2 = n+20
quadratic equation
set equal to 0
n^2 -n -20 = 0
factor
(n-5)(n+4)=0

Answer 4

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