Solve by factoring the trinomial as a binomial square and then use the square root method. Round to the nearest tenth if necessary. x2 + 16x + 64 = 81 A. {9, -9} B. {-8, 9} C. {-17, 1} D. no real solution
\[x^2+16x+64=81\] \[(x+4)^2=81\] \[x+4=9\] or \[x+4=-9\] \[x=5\] or \[x=-13\]
...... wait.... ?
i am wrong sorry
\[(x+8)^2=81\] \[x+8=9\] \[x+8=-9\] \[x=1\] \[x=-17\]
that is what i get for rushing.
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must be getting tired.
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Wow, this is old
looks like somebody misses creepy :D
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