Question

if F(x)=(x^2+1)/(3x-1), find F(-x)

Answer 1

\[F(-x)=\frac{(-x)^2+1}{3(-x)-1}=\frac{x^2+1}{-3x-1}\]

Answer 2

substitute (-x) everywhere you see an x, be sure to use parentheses:

Answer 3

F(x)=(x^2+1)/(3x-1), find F(-x)
F(-x)=((-x)^2+1)/(3(-x)-1)
=(x^2+1)/(-3x-1)

Answer 4

Thanks.