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Find x intercept y = x^2 + 2x + 1
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set y=0
(x+1)^2=0 x=-1
y=(x+1)^2 implies x=-1, -1, so x intercept is -1
I may be wrong, but I have the vertex being (-1,0) wouldnt the x- intercept be different than the vertex of x?
sometimes
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this case it is
ok thanks guys!
u ask for x intercept only due to that ans is x=-1
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