Question

Choose the equation that could be used to find two consecutive odd integers whose sum is 68.

n + (n + 1) = 68

n + (n + 2) = 68

n − (n + 2) = 68

n + 2n = 68

Answer 1

(2m+1)+(2m+3)=68 implies 4m+4=68 implies 4m=64 implies m=16 and the desirous consecutive odd integers are 33 and 35