Question

solve for x: log 4 (x^2+3x) - log 4 (x+5) = 1
plzz hellp

Answer 1

Log(a)-Log(b) = Log(a/b)
log4 (x^2+3x) - log4 (x+5) =1
log4 (x^2+3x)/ (x+5) = 1
(x^2+3x)/(x+5) = 4^1
x^2+3x=4(x+5)
x^2+3x=4x+20
x^2+3x-4x-20=0
x^2-x-20=0
x^2-5x+4x-20=0
x(x-5)+4(x-5)=0
(x-5)(x+4)=0
x=5 or x=-4

Answer 2

thanks!!

Answer 3

You are welcome