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OpenStudy (anonymous):
simplify (1+(1/x))/(1-(1/x^2))
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OpenStudy (anonymous):
no.u.
OpenStudy (anonymous):
x/x-1
OpenStudy (anonymous):
how
OpenStudy (anonymous):
(1+(1/x))/(1-(1/x^2)) =((x+1)/x)/((x^2-1)/x^2) =((x+1)/x (x^2/(x^2-1) can x, and x+1 the answer would be x/x-1
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