Question

2x^2+5x-7/x+3

Answer 1

(2x^2+5x-7)/x+3
2x-1 with remainder -4

Answer 2

Can you show me the steps please

Answer 3

x goes into 2x^2 (2x) times
2x times x+3=2x^2+6x

Now you get:

(2x^2+5x-7)-(2x^2+6x)=-x-7

x goes into -x (-1) times
-1 times x+3=-x-3

Now you get from the above:

(-x-7)-(-x-3)=-4 which is the remainder

Therefore, you get 2x-1 with remainder -4