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solve 3(x-3)=6
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3x-9=6 3x=15 x=5
First you have to divide both sides by 3 to remove thhe 3 multiplying the (x-3), getting (x - 3) = 2. Then, add 3 to both sides to get rid of the -3 next to the x, giving you x = 5.
first, you have to distribute 3 to x-3 so you will get 3x-9 then, 3x-9=6(transpose -9) 3x=6+9 3x=15(divide both sides by 3 you will get x=5
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