Question

Find the X interceps using the factor method, write the equation of the aqis of symmetry.vertex,state if its max or min............O.o I DONT UNDERSTAND

Answer 1

-x^2+3x+10

Answer 2

-x^2+5x-2x+10=(5-x)(x+2)

Answer 3

therefore x-intercepts are 5 and -2

Answer 4

In step 2 where did u get 5-x and x+2 from?

Answer 5

-x^2+5x-2x+10=x(5-x)+2(5-x)=(5-x)(x+2)

Answer 6

understood?

Answer 7

not even a little bit......

Answer 8

i factorized -x^2+3x+10=(5-x)(x+2).
Suppose ur given function is y.
then at x-intercepts y=0...therefore (5-x)(x+2)=0..i.e. x=5,-2
:)

Answer 9

how do you factorize?????????

Answer 10

ok...split 3x as 5x-2x
then -x^2+5x-2x+10

Answer 11

or u can think it of as: put x=-2 and x=5 in ur equation ..u get zero for these two values..so x-intercepts are -2 and 5..

Answer 12

I think you should learn factorizing before doing coordinate geometry :)

Answer 13

ok i got it thank you

Answer 14

now how do u find vertex?

Answer 15

r u sure u want to proceed..cause u need great deal of factoring!!

Answer 16

take y=-x^2+3x+10 then u get by arranging and factoring
(x-3/2)^2=4(-1/4)(y-49/4)

Answer 17

Phil7780 go to my youtbe link on factorising quadratics nd let me know if it helps.
http://www.youtube.com/watch?v=PYTo3b5JO7Y