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The zeros of f(x) = 72x^2-9x are? Please answer clearly and explain the solution clearly and easy to understand. Thanks! (guaranteed medal for a good answer)
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72x(x-9)=0 x=0 n x=9 are the zeros
zeros of a polynomail are the values of the variable for which f(x)=0
based on my answer key the answer is 0 and 1/8 i just don't know how it become like that
oh m wrong 9x(8x-1)=0 x=0, 8x-1=0 x=1/8
what happened to 9x??
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9x=0 x=0 coz 9 is not equal to zero
so it means you will get the value of 2 x's x=0/9 which is x=0 and 8x-1=0 which is x=1/8 am i correct?
right :)
ok thanks!
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