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Students in an English class took a final exam. They took equivalent forms of the exam at monthly intervals thereafter. The average score S(t), in percent, after t months was found to be given by S(t) = 68 − 20 log (t + 1), t ≥ 0. What was the average score when they initially took the test, t = 0? Round your answer to a whole percent, if necessary.
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log(1)=0, so at t=0 we have S(0)=68-20*0 S(0)=68
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youre welcome
What about this one What was the average score after 4 months? after 24 months? Round your answers to two decimal places.
and this one: LOL After what time t was the average score 50%? Round your answers to two decimal places.
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