Question

Solve the equation: (sin^-1 x) - cos ^-1(sqrt(3)/3) = 0
What do I do with sin after I convert cos?

Answer 1

use \[\cos^{-1} A+\cos^{-1} B=\cos^{-1} (AB+\sqrt{1-B^2}\sqrt{1-A^2})\]

Answer 2

I don't understand, I keep getting strange answers

Answer 3

\[\sin^{-1} (x) -\cos^{-1} (\sqrt{3}/3) =0\]
\[\sin^{-1} (x) =\cos^{-1} (\sqrt{3}/3) \]
\[ x =\sin (\cos^{-1} (\sqrt{3}/3) )\]
?