Solve. If there are X teams in a sports league and all the teams play each other twice, a total of N(x) gamers are played, where N(x)=x^2-x. A soccer league has 10 teams, each of which plays the others twice. If the league pays $46 per game for the field and officials, how much will it cost to play the entire schedule?

Question

Solve. If there are X teams in a sports league and all the teams play each other twice, a total of N(x) gamers are played, where N(x)=x^2-x.  A soccer league has 10 teams, each of which plays the others twice.  If the league pays $46 per game for the field and officials, how much will it cost to play the entire schedule?

anonymous · Answer

$$N(10)=10^2-10=100-10-90$$

anonymous · Answer

scuse me i meant 
$$N(10)=10^2-10=90$$

anonymous · Answer

number of games is 90, so cost is  $$90\times 46=4140$$

anonymous · Answer

ok. i see thanks. medal