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OpenStudy (anonymous):
using a graphing calculator, find the real zeros of the function. f(x) = x^6-8x^5+15x^3-2x^2+9
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OpenStudy (anonymous):
looks like there is one just below 8 say at 7.8
OpenStudy (anonymous):
another at about 1.6
OpenStudy (anonymous):
and if you zoom in you will see that those are the only two. it looks at first glance like there are more but there are not. looks like one around -1 but it is an illusion, the graph stays above the x-axis there. very tricky
OpenStudy (anonymous):
ok. i got it. took me a minute. thanks
OpenStudy (anonymous):
took me a minute too. welcome
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