Question

one number is five times another number. a third number is twelve more than the larger of the first two. the sum of the numbers 89. find the numbers. some one please answer this!!!!!!

Answer 1

You don't need to post this multiple times. Just once please, and someone will help here.

Answer 2

someone please answer it then

Answer 3

lucas, are you figuring it out??/

Answer 4

Yes.

Answer 5

good lucas, make it faster i need this stacked :) :P

Answer 6

5A= B
C = 12B
A+B+C= 89
A+5A+60A= 89
66A=89

Answers:

A = 1.35
B = 6.75
C = 81

Answer 7

gw 2011, a lil' faster!!!!!

Answer 8

Let x=the first number
Then 5x=the second number
And 5x+12=the third number

Now adding the above you get:

x+5x+5x+12=89
11x+12=89
11x=77
x=7 This is the first number
5x=(5)(7)=35 This is the second number
5x+12=35+12+47 This is the third number

Answer 9

The third number should be written as 5x+12=35+12=47. The plus 47 should be equals 47.

Answer 10

gw2011 is right, I read the problem wrong and calculated the third number being 12 times rather than 12 more.

Answer 11

kk thanks lucas and gw2011
love you lots