Question

i have a couple of math problems to solve anyone care to help me one on one plz...i really appreciate it

Answer 1

\[h(x)=\sqrt{4x+8}\]
4x+8≥0
4x≥-8
x≥-2
D:(x I x≥-2, x E R)

Answer 2

I REALLY THANK U FOR HELPING ME OUT

Answer 3

you're welcome

Answer 4

I GET CONFUSED BECAUSE I HAVENT DONE THIS MATH IN A LONG WHILE..CAN U FINISH HELPING ME PLZ...ONLY IF U CAN

Answer 5

ok number 11
a) f(x) - g(x) + h(x)
just plug the functions f(x), g(x), and h(x)
you'll get the result = -2x^2 + 27x -4

Answer 6

b) g(x)/h(x)
again, just plug g(x) and h(x)
(10x^2 - 15x)/5x = 2x-3

Answer 7

im confused on number 11a

Answer 8

i inserted f g h

Answer 9

but i got: \[f(23x-4) - G(85) + h(5X)\]

Answer 10

f(x) - g(x) + h(x) =
(8x^2 +7x-4) - (10x^2 -15x) + (5x)
8x^2 +7x-4 - 10x^2 + 15x + 5x

Answer 11

where did you get that?
you just need to substitute f(x) with 8x^2 +7x-4
substitute g(x) with 10x^2 -15x
and substitute h(x) with 5x

Answer 12

i got confused ...now i see it...ughhhhh *sign*

Answer 13

number 12 is about function composition
g(f(3))
first, find f(3)
f(x) = 8x^2 +7x-4 so
f(3) = 8(3)^2 + 7(3) -4
f(3) = 8(9) + 21 -4
f(3) = 72+21-4
f(3) = 89
therefore g(f(3)) = g(89)
g(x) = 10x^2 -15x
g(89) = 10(89)^2 - 15(89)

Answer 14

number 12 is confusing "O

Answer 15

13) because M is the midpoint, AM=MB
2x^2 - 10x + 15 = x^2 - 2x + 3
x^2 - 8x + 12 = 0
(x-6)(x-2)
x = 6 or x=2

Answer 16

this is an article from wikipedia , related to number 12
http://en.wikipedia.org/wiki/Function_composition

Answer 17

thanks

Answer 18

14) AC is an angle bisector, therefore
angle BAD = angle CAD
x^2 = 5x + 24
x^2 - 5x - 24=0
(x-8)(x+3)
x=8 or x=-3

Answer 19

15) BAD is a right angle
4x+8+7x+5 = 90 degree
11x + 13 = 90
11x = 77
x=7

Answer 20

16) 8x+12 + 2x+8 = 180 degree
10x + 20 = 180
10x = 160
x= 16

Answer 21

17) x^2 = 6x-8

Answer 22

for number 12 how did we get 8 if the problem is f(x) = 3x -4 and g(x) = x to the 2nd -5 you dont have to redo the problem just need to know how 8 got there

Answer 23

oh, sorry, i did it wrong, i didnt see the f(x) and g(x) in number 11 and 12 are different, i'll do it again

Answer 24

ok thanks

Answer 25

f(x) = 3x -4 and g(x) = x^2 - 5
f(3) = 3(3) - 4 = 9-4 = 5
because f(3) = 5, g(f(3)) = g(5)
g(5) = (5)^2 - 5 = 25-5 = 20

Answer 26

thank you very much for correcting it ")

Answer 27

19, because it's an iscoceles triangle, angle C must be the same as angle A.
a triangle has an angle of 180 degree, so :
A + B + C = 180 degree
2x^2 + x^2 + 2x^2 = 180

Answer 28

god ur good at this

Answer 29

can i borrow ur brains for my finals...lol ")

Answer 30

this is for number 20

Answer 31

lol, not really good, actually, this is kinda like SAT problems

Answer 32

damn then i am dumb "(

Answer 33

you just need to keep practicing, you'll be good at this.
sorry i can't continue this, i gotta go. bye

Answer 34

ok thank u very much for all ur help