find the least number between 200 and 500 which leaves a remainder of 3 in each case when divided by 8,10,12 and 30

Question

owlfred · Answer

Hoot! You just asked your first question! Hang tight while I find people to answer it for you. You can thank people who give you good answers by clicking the 'Good Answer' button on the right!

anonymous · Answer

First find the LCM of 8,10, 12 and 30 (this is 120)
Find the lowest multiple of 120 between 300 and 500 (this 360)
Add 3 to this
363
That's it!

l · Answer

LCM(8,10,12,30) = 120
120 < 200
120 * 2 = 240
200 < 240 < 500
-> 240+3 = 243
Solution is 243, i think.

anonymous · Answer

i you are right I read it as 300-500

anonymous · Answer

Hey umm Why'd yu multiply by 2 aftr getting the LCM?