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if f(x)=9x+1, find f^-1(f(3))
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f(3) = 28; so im guessing its 28 again, but let me chk
f(3) = 28 f-1 = (x-1)/9 28-1 ----- = 27/9 = 3 9
it is 28
... its 3 :)
i had the right thought, but the wrong concept lol
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3
27 divided by 9 is 3 yup right
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