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c^2-8c-20=0 solve
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(c-10)(c+2)
So the roots are 10 and -2, because: c-10=0 c=10 c+2=0 c=-2
so the answer would be c= -2, 10?
c^2-8c-20=0 c^2-10c+2c-20=0 c(c-10)+2(c-10)=0 (c+2)(c-10)=0 c=-2, c=10
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